Four Squares each containing a
arranged in a rectangle so that they share two
In this example the four Pairs (coloured sea green) are on H9, J2, J9 and (possibly) H2. If H2 were to contain the same Pair (4 and 8), then the SuDoku would not have
a unique solution.
To understand why this is true, consider the effect of H2 being a 4. This would force H9 and J2 to be an 8 and force J9 to be a 4.
This would eliminate all other 4s and 8s in the same two Rows, Columns and Boxes. Now consider the effect of H2 being an 8. H9 and J2 would be a 4 and
J9 would be an 8 - but once again all other 4s and 8s in the same two Rows, Columns and Boxes would be eliminated. In other words, the effect on the
rest of the SuDoku is identical - irrespective of whether H2 is a 4 or an 8. So there would be two solutions to this SuDoku, because interchanging the
4s and 8s in the four Squares would have no effect on the rest of the SuDoku. Since SuDokus are assumed to have a unique solution, this cannot be allowed
to happen - the Quad Pairs arrangement is an impossible scenario. Therefore 4 and 8 in H2 (outlined in orange) are impossible
and can be
For this logic to work, the four Squares must share only two Columns, two Rows and two Boxes. If they shared four Boxes (for example if the four
Squares were F2, F9, J2 and J9), then the logic would not be the same - because eliminations in the rest of the SuDoku would be different depending on
which Boxes the 4s and 8s were in - so the 4s and 8s would not be interchangeable.